-2x^2+4x=2x-180

Solution for -2x^2+4x=2x-180 equation:

-2x^2+4x=2x-180

We move all terms to the left:

-2x^2+4x-(2x-180)=0

We get rid of parentheses

-2x^2+4x-2x+180=0

We add all the numbers together, and all the variables

-2x^2+2x+180=0

a = -2; b = 2; c = +180;
Δ = b2-4ac
Δ = 22-4·(-2)·180
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-38}{2*-2}=\frac{-40}{-4}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+38}{2*-2}=\frac{36}{-4}
=-9
$